Q206. Suppose the agents in a population have four behaviors - W, X, Y, Z - and that each behavior is either present or absent. Further suppose that there is some pressure toward consistency such that having a "don't do" behavior next to a "do do" behavior is uncomfortable and so agents have some internal urge to change their behavior to be more consistent.

Let's say that a behavior that is the only one of its type (a 0 among three 1s, for example) has a 50 percent chance of switching to make the set fully consistent. Each behavior that's one of an even split (e.g., a 0 in a 0011 agent) has a 10% chance of switching. We can put it this way: there is a 10% chance the first behavior changes, 10% the second, etc. and 60% chance no change happens.

Use the two random number table below to work out the next state n the grid below, determine the probability of interaction between each pair of neighbors (assume no diagonal interaction for now). For 50% chance use "random number above 50 = change, below 50 = stay." For the 10% chances, 0<10 is change first, 10<20 change 2, etc.

 69 72 43 97 87 37 86 35 23 41 88 36 94 60 60 84 26 3 87 12 8 10 56 52 29 26 5 30 15 58 95 3 95 18 69 71 42 55 64 21 68 75 90 19 64 75 13 77 1 89
 A 1110 B 1010 C 0010 D 1001 E 0000 F 1111 G 1001 H 1011
page revision: 5, last edited: 18 Nov 2012 22:48