Q206. Suppose the agents in a population have four behaviors - W, X, Y, Z - and that each behavior is either present or absent. Further suppose that there is some pressure toward consistency such that having a "don't do" behavior next to a "do do" behavior is uncomfortable and so agents have some internal urge to change their behavior to be more consistent.
Let's say that a behavior that is the only one of its type (a 0 among three 1s, for example) has a 50 percent chance of switching to make the set fully consistent. Each behavior that's one of an even split (e.g., a 0 in a 0011 agent) has a 10% chance of switching. We can put it this way: there is a 10% chance the first behavior changes, 10% the second, etc. and 60% chance no change happens.
Use the two random number table below to work out the next state n the grid below, determine the probability of interaction between each pair of neighbors (assume no diagonal interaction for now). For 50% chance use "random number above 50 = change, below 50 = stay." For the 10% chances, 0<10 is change first, 10<20 change 2, etc.
| 69 | 72 | 43 | 97 | 87 |
| 37 | 86 | 35 | 23 | 41 |
| 88 | 36 | 94 | 60 | 60 |
| 84 | 26 | 3 | 87 | 12 |
| 8 | 10 | 56 | 52 | 29 |
| 26 | 5 | 30 | 15 | 58 |
| 95 | 3 | 95 | 18 | 69 |
| 71 | 42 | 55 | 64 | 21 |
| 68 | 75 | 90 | 19 | 64 |
| 75 | 13 | 77 | 1 | 89 |
| A 1110 |
B 1010 |
C 0010 |
D 1001 |
| E 0000 |
F 1111 |
G 1001 |
H 1011 |