**Q205.** Suppose the agents in a population have four behaviors - W, X, Y, Z - and that each behavior is either present or absent. When two agents meet they may have all the same behaviors, none of the same behaviors, or 1 or 2 behaviors in common. Suppose the probability of interaction is proportional to their similarity. IF they do interact, they flip a coin and who ever wins gets imitated by the other agent.

Use the two random number tables below (the left table for doing a Monte Carlo simulation of whether interaction occurs and the left table to determine which agent is the leader and which is the follower) to work out the next state n the grid below, determine the probability of interaction between each pair of neighbors (assume no diagonal interaction for now)

69 | 72 | 43 | 97 | 87 | 0 | 0 | 0 | 1 | 1 | |

37 | 86 | 35 | 23 | 41 | 1 | 1 | 0 | 0 | 1 | |

88 | 36 | 94 | 60 | 60 | 1 | 1 | 1 | 0 | 0 | |

84 | 26 | 3 | 87 | 12 | 0 | 0 | 1 | 1 | 0 | |

8 | 10 | 56 | 52 | 29 | 1 | 1 | 1 | 0 | 0 | |

26 | 5 | 30 | 15 | 58 | 0 | 1 | 1 | 1 | 1 | |

95 | 3 | 95 | 18 | 69 | 0 | 0 | 1 | 0 | 0 | |

71 | 42 | 55 | 64 | 21 | 0 | 0 | 1 | 1 | 0 | |

68 | 75 | 90 | 19 | 64 | 0 | 0 | 1 | 1 | 0 | |

75 | 13 | 77 | 1 | 89 | 0 | 0 | 0 | 0 | 0 |

A 1110 |
B 1010 |
C 0010 |
D 1001 |

E 0000 |
F 1111 |
G 1001 |
H 1011 |

I 1000 |
J 1000 |
K 1110 |
L 0000 |

M 0010 |
N 1100 |
O 0100 |
P 0111 |